For two mechanical rooms with a combined volume needing combustion air for 110,000 BTU/h, can they have sufficient air if one room is 12' x 14' x 8' and the other is 30' x 20' x 8'?

Prepare for the Kansas Mechanical Journeyman Test with our comprehensive study tools. Use flashcards and multiple-choice questions, each including hints and explanations, to help you pass confidently!

The combined volume of the two mechanical rooms is critical in determining their ability to provide sufficient combustion air. To find the total volume, one must calculate the volume of each room and sum them up.

For the first room, the calculations are as follows:

  • Room dimensions: 12' x 14' x 8'

  • Volume = 12 * 14 * 8 = 1,344 cubic feet

For the second room:

  • Room dimensions: 30' x 20' x 8'

  • Volume = 30 * 20 * 8 = 4,800 cubic feet

Adding these volumes together yields:

1,344 + 4,800 = 6,144 cubic feet.

When evaluating the combustion air requirements, it is important to recognize that combustion appliances typically require a certain volume of air for every unit of BTU output. The volume of air needed for combustion is generally calculated based on the appliances' energy output in BTUs and the configuration of the space.

A common guideline used in determining whether sufficient combustion air is available is that 50 cubic feet of air is typically needed for every 1,000 BTU/h of input. Given that the total BTU requirement is 110,000:

Subscribe

Get the latest from Examzify

You can unsubscribe at any time. Read our privacy policy